Spring design question
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Spring design question

 
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Jason L
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Posted: Fri May 27, 2005 10:20 pm    Post subject: Spring design question Reply with quote

I want to create a spring with both closed and ground ends using a family
table. Most of our company's springs are purchased from Lee Spring Co. and
they only supply OD, Wire Dia, Free Length, Spring Rate, and Solid Height. I
need to be able to figure out the total number of coils based on this info
to include in the part relations. Is there a formula? Does anyone have a
similar Pro/E model or know where I can download one?

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Stu
Guest





Posted: Fri May 27, 2005 10:59 pm    Post subject: Re: Spring design question Reply with quote

On Fri, 27 May 2005 13:20:18 -0400, "Jason L" <tectranbrake@yahoo.com>
wrote:

Quote:
I want to create a spring with both closed and ground ends using a family
table. Most of our company's springs are purchased from Lee Spring Co. and
they only supply OD, Wire Dia, Free Length, Spring Rate, and Solid Height. I
need to be able to figure out the total number of coils based on this info
to include in the part relations. Is there a formula? Does anyone have a
similar Pro/E model or know where I can download one?


Have you tried to use the solid height divided by the wire diam = num
of turns?
( solid height should be the spring in a fully compressed state with
no gap between the coils )

I use that and it is close enough for a visual rep of a wire spring.


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David Janes
Guest





Posted: Sat May 28, 2005 4:10 pm    Post subject: Re: Spring design question Reply with quote

Quote:
"Stu" <Stu@kapco-tool.com> wrote
On Fri, 27 May 2005 13:20:18 -0400, "Jason L" <tectranbrake@yahoo.com
wrote:

I want to create a spring with both closed and ground ends using a family
table. Most of our company's springs are purchased from Lee Spring Co. and
they only supply OD, Wire Dia, Free Length, Spring Rate, and Solid Height. I
need to be able to figure out the total number of coils based on this info
to include in the part relations. Is there a formula? Does anyone have a
similar Pro/E model or know where I can download one?


Have you tried to use the solid height divided by the wire diam = num
of turns?
( solid height should be the spring in a fully compressed state with
no gap between the coils )

I use that and it is close enough for a visual rep of a wire spring.

"Machinery's Handbook" has a complete section on springs and spring design with

all the formulas. The way Stu suggests is roughly correct or completely right for
plain springs. For ground ends, it's the number of turns minus one and for closed
ends, closed and ground or squared and ground, it's the number of turns minus two.

David Janes

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Jason L
Guest





Posted: Tue May 31, 2005 4:10 pm    Post subject: Re: Spring design question Reply with quote

Thanks Stu and David,

I emailed Lee Spring with the question and they called me within an hour
with the same answer you both gave. Your help is always appreciated.

Jason





"David Janes" <djanes@cox.net.invarris> wrote in message
news:IT_le.8406$7p.1198@fed1read06...
Quote:
"Stu" <Stu@kapco-tool.com> wrote
On Fri, 27 May 2005 13:20:18 -0400, "Jason L" <tectranbrake@yahoo.com
wrote:

I want to create a spring with both closed and ground ends using a family
table. Most of our company's springs are purchased from Lee Spring Co.
and
they only supply OD, Wire Dia, Free Length, Spring Rate, and Solid
Height. I
need to be able to figure out the total number of coils based on this
info
to include in the part relations. Is there a formula? Does anyone have a
similar Pro/E model or know where I can download one?


Have you tried to use the solid height divided by the wire diam = num
of turns?
( solid height should be the spring in a fully compressed state with
no gap between the coils )

I use that and it is close enough for a visual rep of a wire spring.

"Machinery's Handbook" has a complete section on springs and spring design
with all the formulas. The way Stu suggests is roughly correct or
completely right for plain springs. For ground ends, it's the number of
turns minus one and for closed ends, closed and ground or squared and
ground, it's the number of turns minus two.

David Janes
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